Richest Customer Wealth

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class Solution:
    def maximumWealth(self, accounts: List[List[int]]) -> int:
        max_wealth = 0

        for row in accounts:
            customer_wealth = sum(row)
            if customer_wealth > max_wealth:
                max_wealth = customer_wealth

        return max_wealth

Explanation

1. Initialize max_wealth to 0, which will keep track of the maximum wealth found so far.
2. Iterate through each row in accounts, representing a customer’s bank accounts.
3. Compute the sum of each row, representing the total wealth for that customer.
4. If the computed wealth is greater than the current max_wealth, update max_wealth.
5. Return max_wealth as the final result, representing the wealth of the richest customer.

title: Richest Customer Wealth excerpt: The basic building blocks covered in this article are calculate sum and find max. tags: calculate-sum find-max

You are given an m x n integer grid accounts where accounts[i][j] is the amount of money the i​​​​​​​​​​​th​​​​ customer has in the j​​​​​​​​​​​th​​​​ bank. Return the wealth that the richest customer has. A customer’s wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.

Example 1:
Input: accounts = [[1,2,3],[3,2,1]]
Output: 6
Explanation:
1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.

Example 2:
Input: accounts = [[1,5],[7,3],[3,5]]
Output: 10
Explanation: 
1st customer has wealth = 6
2nd customer has wealth = 10 
3rd customer has wealth = 8
The 2nd customer is the richest with a wealth of 10.

Example 3:
Input: accounts = [[2,8,7],[7,1,3],[1,9,5]]
Output: 17

Constraints

• m == accounts.length
• n == accounts[i].length
• 1 <= m, n <= 50
• 1 <= accounts[i][j] <= 100

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def maximum_wealth(accounts)
  wealth = []
  
  accounts.each do |account|
    wealth << account.sum
  end
  
  wealth.max
end

Calculate the wealth of each customer Find the maximum element in the array.

Building Blocks

• Calculate Sum
• Find Max