Largest Subarray Length K

This problem is asking us to find the largest subarray of a given size k from an array nums of unique integers. The “largeness” of a subarray is determined by the first differing element when comparing two subarrays.

The Python solution for this problem involves a sliding window approach. We scan through the array to find the start index of the largest subarray. The largest subarray of size k is the one starting at the maximum element in the nums[0:len(nums)-k+1] range.

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from typing import List

class Solution:
    def largestSubarray(self, nums: List[int], k: int) -> List[int]:
        # Calculate the start index of the largest subarray
        start_idx = nums.index(max(nums[:len(nums) - k + 1]))
        # Return the subarray starting from the calculated start index and of length k
        return nums[start_idx: start_idx + k]

In this solution, we find the index of the maximum element in the range nums[0:len(nums)-k+1] and consider this as the starting index of our largest subarray. Then, we return the subarray of length k starting from this index. This approach guarantees the largest subarray because we start at the highest possible value that allows a subarray of length k, then select k elements starting from that index.