Generate a String With Characters That Have Odd Counts

The idea is to generate a string of ‘a’ characters of length n if n is odd, or a string of ‘a’ characters of length n - 1 followed by a ‘b’ if n is even. This ensures that every character in the string occurs an odd number of times, which is the problem’s requirement.

Python solution:

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class Solution:
    def generateTheString(self, n: int) -> str:
        # If n is odd
        if n % 2 != 0:
            # Return a string with 'a' repeated n times
            return 'a' * n
        else:
            # If n is even, return a string with 'a' repeated n-1 times and a 'b' at the end
            return 'a' * (n - 1) + 'b'

In this solution, we use the modulo operator to determine if n is even or odd. If n is odd, we return a string with ‘a’ repeated n times. If n is even, we return a string with ‘a’ repeated n - 1 times, followed by a ‘b’. This ensures that each character in the string occurs an odd number of times.