Count Common Words With One Occurrence

Here’s a way to achieve the given task by defining the countWords function:

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from collections import Counter

class Solution:
    def countWords(self, words1: List[str], words2: List[str]) -> int:
        # Count the occurrence of each word in words1
        count1 = Counter(words1)

        # Count the occurrence of each word in words2
        count2 = Counter(words2)

        # Initialize a variable to hold the count of words that appear exactly once in both arrays
        result = 0

        # Iterate through the count1 dictionary
        for word, count in count1.items():
            # Check if the word appears exactly once in both arrays
            if count == 1 and count2[word] == 1:
                # Increment the result by 1
                result += 1

        return result

Explanation

This code uses the Counter class from the collections module to count the occurrences of each word in words1 and words2.
It initializes a variable result to keep track of the number of strings that appear exactly once in both arrays.
Then, it iterates through the count of words in words1 and checks if any word appears exactly once in both words1 and words2. If so, it increments the result by 1.
Finally, it returns the result, which is the number of strings that appear exactly once in each of the two arrays.