Check if There Is a Valid Parentheses String Path

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class Solution:
    def hasValidPath(self, grid: List[List[str]]) -> bool:
        self.n = len(grid)
        self.m = len(grid[0])
        self.dp = [[[-1 for _ in range(205)] for _ in range(self.m)] for _ in range(self.n)]

        def solve(i, j, k):
            if i >= self.n or j >= self.m:
                return False

            if grid[i][j] == '(':
                k += 1
            else:
                k -= 1

            if k < 0:
                return False

            if i == self.n - 1 and j == self.m - 1:
                return k == 0

            if self.dp[i][j][k] != -1:
                return self.dp[i][j][k]

            self.dp[i][j][k] = solve(i + 1, j, k) or solve(i, j + 1, k)
            return self.dp[i][j][k]

        return solve(0, 0, 0)