Check if Number Has Equal Digit Count and Digit Value

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class Solution:
    def digitCount(self, num: str) -> bool:
        # Create a list to keep track of the occurrence of each digit
        occurrences = [0] * 10

        # Count the occurrences of each digit in the string num
        for digit in num:
            occurrences[int(digit)] += 1

        # Check if the condition holds for every index i
        for i in range(len(num)):
            if occurrences[i] != int(num[i]):
                return False

        return True